NEET (UG)

ICSE Class 10 Electrochemistry — Mock Test

Free online mock test for Electrochemistry (ICSE Class 10 Chemistry) — 102 competency-based questions with instant marking. Try the samples below, then take the full test free.

Sample questions

  1. 1.All of the following statements about the Kohlrausch law of independent migration of ions are correct EXCEPT:
    • A.Limiting molar conductivity of an electrolyte is the sum of contributions of its anion and cation
    • B.It allows calculation of Lm for any electrolyte from the values of individual ions
    • C.It can be used to determine the dissociation constant of a weak electrolyte
    • D.It states that conductivity of a solution increases with dilution
  2. 2.Consider the following statements about corrosion of iron and identify the correct combination. (I) At the anodic spot iron is oxidised to Fe2+. (II) At the cathodic spot oxygen is reduced in the presence of H+. (III) Rust is hydrated ferric oxide.
    • A.I, II and III are all correct
    • B.Only I and II are correct
    • C.Only II and III are correct
    • D.Only I is correct
  3. 3.During electrolysis of aqueous NaCl, at the cathode there is competition between Na+ + e- gives Na (E = -2.71 V) and H+ + e- gives half H2 (E = 0.00 V). Which is reduced, and why?
    • A.Na+, because it has the more negative potential
    • B.H+ (water), because the reduction with the higher E value is preferred
    • C.Both are reduced equally
    • D.Neither is reduced; only Cl- reacts
  4. 4.For the Daniell cell, the standard reduction potentials are E0(Cu2+/Cu) = +0.34 V and E0(Zn2+/Zn) = -0.76 V. Copper is the cathode and zinc is the anode. Calculate the standard cell potential E0(cell).
    • A.1.10 V
    • B.0.42 V
    • C.-1.10 V
    • D.0.34 V
  5. 5.When a lead storage battery is recharged, the reaction occurring during discharge, Pb + PbO2 + 2H2SO4 gives 2PbSO4 + 2H2O, is reversed. During recharging:
    • A.PbSO4 on the electrodes is converted back into Pb and PbO2, and sulphuric acid is regenerated
    • B.PbO2 is converted into PbSO4 at both electrodes
    • C.water is consumed to form more PbSO4
    • D.lead is deposited as PbO at the cathode

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